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1211013000000 = 263256239563
BaseRepresentation
bin10001100111110101111…
…111111110101101000000
311021202211120121110212100
4101213311333332231000
5124320123312000000
62324155351230400
7153331013441526
oct21476577765500
94252746543770
101211013000000
114276512a3a91
12176851978400
138a27611455b
1442883020316
152177b996a00
hex119f5ffeb40

1211013000000 has 588 divisors, whose sum is σ = 4364775380160. Its totient is φ = 321014400000.

The previous prime is 1211012999983. The next prime is 1211013000007. The reversal of 1211013000000 is 3101121.

It is a Harshad number since it is a multiple of its sum of digits (9).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1211013000007) by changing a digit.

It is a polite number, since it can be written in 83 ways as a sum of consecutive naturals, for example, 2150999719 + ... + 2151000281.

Almost surely, 21211013000000 is an apocalyptic number.

1211013000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1211013000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2182387690080).

1211013000000 is an abundant number, since it is smaller than the sum of its proper divisors (3153762380160).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1211013000000 is an frugal number, since it uses more digits than its factorization.

1211013000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 850 (or 812 counting only the distinct ones).

The product of its (nonzero) digits is 6, while the sum is 9.

Adding to 1211013000000 its reverse (3101121), we get a palindrome (1211016101121).

The spelling of 1211013000000 in words is "one trillion, two hundred eleven billion, thirteen million", and thus it is an aban number.