12110211333133 has 4 divisors (see below), whose sum is σ = 12110294603680. Its totient is φ = 12110128062588.

The previous prime is 12110211333119. The next prime is 12110211333137. The reversal of 12110211333133 is 33133311201121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12110211333133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12110211333098 and 12110211333107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12110211333137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41416743 + ... + 41708116.

It is an arithmetic number, because the mean of its divisors is an integer number (3027573650920).

Almost surely, 2^{12110211333133} is an apocalyptic number.

It is an amenable number.

12110211333133 is a deficient number, since it is larger than the sum of its proper divisors (83270547).

12110211333133 is an equidigital number, since it uses as much as digits as its factorization.

12110211333133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 83270546.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 12110211333133 its reverse (33133311201121), we get a palindrome (45243522534254).

The spelling of 12110211333133 in words is "twelve trillion, one hundred ten billion, two hundred eleven million, three hundred thirty-three thousand, one hundred thirty-three".