1211021300221 has 4 divisors (see below), whose sum is σ = 1236787710912. Its totient is φ = 1185254889532.

The previous prime is 1211021300219. The next prime is 1211021300233. The reversal of 1211021300221 is 1220031201121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1211021300221 - 2¹ = 1211021300219 is a prime.

It is a super-2 number, since 2×1211021300221² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1211021300195 and 1211021300204.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1211021303221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12883205275 + ... + 12883205368.

It is an arithmetic number, because the mean of its divisors is an integer number (309196927728).

Almost surely, 2^{1211021300221} is an apocalyptic number.

It is an amenable number.

1211021300221 is a deficient number, since it is larger than the sum of its proper divisors (25766410691).

1211021300221 is an equidigital number, since it uses as much as digits as its factorization.

1211021300221 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25766410690.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 1211021300221 its reverse (1220031201121), we get a palindrome (2431052501342).

The spelling of 1211021300221 in words is "one trillion, two hundred eleven billion, twenty-one million, three hundred thousand, two hundred twenty-one".