12110213149 has 2 divisors, whose sum is σ = 12110213150. Its totient is φ = 12110213148.

The previous prime is 12110213119. The next prime is 12110213221. The reversal of 12110213149 is 94131201121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11297564100 + 812649049 = 106290^2 + 28507^2 .

It is a cyclic number.

It is not a de Polignac number, because 12110213149 - 2⁵ = 12110213117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12110213119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055106574 + 6055106575.

It is an arithmetic number, because the mean of its divisors is an integer number (6055106575).

Almost surely, 2^12110213149 is an apocalyptic number.

It is an amenable number.

12110213149 is a deficient number, since it is larger than the sum of its proper divisors (1).

12110213149 is an equidigital number, since it uses as much as digits as its factorization.

12110213149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 25.

The spelling of 12110213149 in words is "twelve billion, one hundred ten million, two hundred thirteen thousand, one hundred forty-nine".