Base | Representation |
---|---|
bin | 10001100111110110100… |
… | …010010101000010111011 |
3 | 11021202212012112221121001 |
4 | 101213312202111002323 |
5 | 124320133113120121 |
6 | 2324200312225431 |
7 | 153331153123462 |
oct | 21476642250273 |
9 | 4252765487531 |
10 | 1211022004411 |
11 | 42765639414a |
12 | 17685499b277 |
13 | 8a277c47bcb |
14 | 428842c59d9 |
15 | 2177c674991 |
hex | 119f68950bb |
1211022004411 has 2 divisors, whose sum is σ = 1211022004412. Its totient is φ = 1211022004410.
The previous prime is 1211022004399. The next prime is 1211022004429. The reversal of 1211022004411 is 1144002201121.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1211022004411 is a prime.
It is a super-2 number, since 2×12110220044112 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1211022004441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605511002205 + 605511002206.
It is an arithmetic number, because the mean of its divisors is an integer number (605511002206).
Almost surely, 21211022004411 is an apocalyptic number.
1211022004411 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211022004411 is an equidigital number, since it uses as much as digits as its factorization.
1211022004411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 128, while the sum is 19.
Adding to 1211022004411 its reverse (1144002201121), we get a palindrome (2355024205532).
The spelling of 1211022004411 in words is "one trillion, two hundred eleven billion, twenty-two million, four thousand, four hundred eleven".
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