Base | Representation |
---|---|
bin | 11011100010010001001101… |
… | …101011110100010101100101 |
3 | 120212210020221121210212102101 |
4 | 123202101031223310111211 |
5 | 111333114302002211323 |
6 | 1105321325550012101 |
7 | 34336226303661166 |
oct | 3342211553642545 |
9 | 525706847725371 |
10 | 121102201210213 |
11 | 35650178500aa3 |
12 | 116ba5021a7031 |
13 | 5275b7226b3a2 |
14 | 21c9540a0b76d |
15 | e0022d4b1dad |
hex | 6e244daf4565 |
121102201210213 has 2 divisors, whose sum is σ = 121102201210214. Its totient is φ = 121102201210212.
The previous prime is 121102201210187. The next prime is 121102201210241. The reversal of 121102201210213 is 312012102201121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 97381726495524 + 23720474714689 = 9868218^2 + 4870367^2 .
It is a cyclic number.
It is not a de Polignac number, because 121102201210213 - 25 = 121102201210181 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121102201310213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60551100605106 + 60551100605107.
It is an arithmetic number, because the mean of its divisors is an integer number (60551100605107).
Almost surely, 2121102201210213 is an apocalyptic number.
It is an amenable number.
121102201210213 is a deficient number, since it is larger than the sum of its proper divisors (1).
121102201210213 is an equidigital number, since it uses as much as digits as its factorization.
121102201210213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 121102201210213 its reverse (312012102201121), we get a palindrome (433114303411334).
The spelling of 121102201210213 in words is "one hundred twenty-one trillion, one hundred two billion, two hundred one million, two hundred ten thousand, two hundred thirteen".
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