Base | Representation |
---|---|
bin | 10001100111110110100… |
… | …011100100100010101111 |
3 | 11021202212020011111021001 |
4 | 101213312203210202233 |
5 | 124320133204030111 |
6 | 2324200323221131 |
7 | 153331155651013 |
oct | 21476643444257 |
9 | 4252766144231 |
10 | 1211022330031 |
11 | 427656596858 |
12 | 176854b177a7 |
13 | 8a278030197 |
14 | 4288436c543 |
15 | 2177c6db1c1 |
hex | 119f68e48af |
1211022330031 has 2 divisors, whose sum is σ = 1211022330032. Its totient is φ = 1211022330030.
The previous prime is 1211022329969. The next prime is 1211022330059. The reversal of 1211022330031 is 1300332201121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1211022330031 - 219 = 1211021805743 is a prime.
It is a super-2 number, since 2×12110223300312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1211022329990 and 1211022330008.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1211022331031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605511165015 + 605511165016.
It is an arithmetic number, because the mean of its divisors is an integer number (605511165016).
Almost surely, 21211022330031 is an apocalyptic number.
1211022330031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211022330031 is an equidigital number, since it uses as much as digits as its factorization.
1211022330031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 1211022330031 its reverse (1300332201121), we get a palindrome (2511354531152).
The spelling of 1211022330031 in words is "one trillion, two hundred eleven billion, twenty-two million, three hundred thirty thousand, thirty-one".
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