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12110302132997 is a prime number
BaseRepresentation
bin1011000000111010011001…
…0000011011101100000101
31120212201210210000000201112
42300032212100123230011
53041403344321223442
641431221311334405
72356640401455125
oct260164620335405
946781723000645
1012110302132997
113949a4a925a02
121437083821405
1369acc56833c3
142dc1dad6cc85
1516003b7e9082
hexb03a641bb05

12110302132997 has 2 divisors, whose sum is σ = 12110302132998. Its totient is φ = 12110302132996.

The previous prime is 12110302132979. The next prime is 12110302133047. The reversal of 12110302132997 is 79923120301121.

Together with previous prime (12110302132979) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9092208978241 + 3018093154756 = 3015329^2 + 1737266^2 .

It is a cyclic number.

It is not a de Polignac number, because 12110302132997 - 222 = 12110297938693 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12110302132967) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055151066498 + 6055151066499.

It is an arithmetic number, because the mean of its divisors is an integer number (6055151066499).

Almost surely, 212110302132997 is an apocalyptic number.

It is an amenable number.

12110302132997 is a deficient number, since it is larger than the sum of its proper divisors (1).

12110302132997 is an equidigital number, since it uses as much as digits as its factorization.

12110302132997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 40824, while the sum is 41.

The spelling of 12110302132997 in words is "twelve trillion, one hundred ten billion, three hundred two million, one hundred thirty-two thousand, nine hundred ninety-seven".