Base | Representation |
---|---|
bin | 111000011001001001… |
… | …1110000001011001011 |
3 | 102120120212220001222022 |
4 | 1300302103300023023 |
5 | 3441004344420042 |
6 | 131344540115055 |
7 | 11515022363606 |
oct | 1606223601313 |
9 | 376525801868 |
10 | 121103123147 |
11 | 473a5612946 |
12 | 1b579235a8b |
13 | b55c8bc766 |
14 | 5c0ba5933d |
15 | 323bc56cd2 |
hex | 1c324f02cb |
121103123147 has 2 divisors, whose sum is σ = 121103123148. Its totient is φ = 121103123146.
The previous prime is 121103123087. The next prime is 121103123291. The reversal of 121103123147 is 741321301121.
It is a weak prime.
It is an emirp because it is prime and its reverse (741321301121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 121103123147 - 218 = 121102861003 is a prime.
It is not a weakly prime, because it can be changed into another prime (121103120147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60551561573 + 60551561574.
It is an arithmetic number, because the mean of its divisors is an integer number (60551561574).
Almost surely, 2121103123147 is an apocalyptic number.
121103123147 is a deficient number, since it is larger than the sum of its proper divisors (1).
121103123147 is an equidigital number, since it uses as much as digits as its factorization.
121103123147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 26.
Adding to 121103123147 its reverse (741321301121), we get a palindrome (862424424268).
The spelling of 121103123147 in words is "one hundred twenty-one billion, one hundred three million, one hundred twenty-three thousand, one hundred forty-seven".
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