Base | Representation |
---|---|
bin | 1011000000111010011011… |
… | …0111010101001100010011 |
3 | 1120212201211111012002101102 |
4 | 2300032212313111030103 |
5 | 3041403404424030003 |
6 | 41431222314055015 |
7 | 2356640554235036 |
oct | 260164667251423 |
9 | 46781744162342 |
10 | 12110312330003 |
11 | 3949a55660088 |
12 | 143708711a46b |
13 | 69acc7813834 |
14 | 2dc1dc46501d |
15 | 16003c660588 |
hex | b03a6dd5313 |
12110312330003 has 4 divisors (see below), whose sum is σ = 12315571861080. Its totient is φ = 11905052798928.
The previous prime is 12110312329979. The next prime is 12110312330041. The reversal of 12110312330003 is 30003321301121.
12110312330003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12110312330003 - 234 = 12093132460819 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12110312330603) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 102629765450 + ... + 102629765567.
It is an arithmetic number, because the mean of its divisors is an integer number (3078892965270).
Almost surely, 212110312330003 is an apocalyptic number.
12110312330003 is a deficient number, since it is larger than the sum of its proper divisors (205259531077).
12110312330003 is an equidigital number, since it uses as much as digits as its factorization.
12110312330003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 205259531076.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 12110312330003 its reverse (30003321301121), we get a palindrome (42113633631124).
The spelling of 12110312330003 in words is "twelve trillion, one hundred ten billion, three hundred twelve million, three hundred thirty thousand, three".
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