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12110322521243 is a prime number
BaseRepresentation
bin1011000000111010011101…
…1110001101010010011011
31120212201212012100212010202
42300032213132031102123
53041403420031134433
641431223320332415
72356641036662102
oct260164736152233
946781765325122
1012110322521243
113949a603909a1
12143708a61410b
1369acc997145b
142dc1dd959039
1516003d4c4ee8
hexb03a778d49b

12110322521243 has 2 divisors, whose sum is σ = 12110322521244. Its totient is φ = 12110322521242.

The previous prime is 12110322521197. The next prime is 12110322521261. The reversal of 12110322521243 is 34212522301121.

It is a strong prime.

It is an emirp because it is prime and its reverse (34212522301121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12110322521243 - 212 = 12110322517147 is a prime.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (12110322521263) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055161260621 + 6055161260622.

It is an arithmetic number, because the mean of its divisors is an integer number (6055161260622).

Almost surely, 212110322521243 is an apocalyptic number.

12110322521243 is a deficient number, since it is larger than the sum of its proper divisors (1).

12110322521243 is an equidigital number, since it uses as much as digits as its factorization.

12110322521243 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 12110322521243 its reverse (34212522301121), we get a palindrome (46322844822364).

The spelling of 12110322521243 in words is "twelve trillion, one hundred ten billion, three hundred twenty-two million, five hundred twenty-one thousand, two hundred forty-three".