Base | Representation |
---|---|
bin | 111000011001001010… |
… | …0001010110000001101 |
3 | 102120120220002121022101 |
4 | 1300302110022300031 |
5 | 3441004411411023 |
6 | 131344542315101 |
7 | 11515023326161 |
oct | 1606224126015 |
9 | 376526077271 |
10 | 121103232013 |
11 | 473a5687715 |
12 | 1b579288a91 |
13 | b55c92a18a |
14 | 5c0ba86ca1 |
15 | 323bc791ad |
hex | 1c3250ac0d |
121103232013 has 2 divisors, whose sum is σ = 121103232014. Its totient is φ = 121103232012.
The previous prime is 121103231983. The next prime is 121103232059. The reversal of 121103232013 is 310232301121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 118458495684 + 2644736329 = 344178^2 + 51427^2 .
It is an emirp because it is prime and its reverse (310232301121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 121103232013 - 213 = 121103223821 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121103230013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60551616006 + 60551616007.
It is an arithmetic number, because the mean of its divisors is an integer number (60551616007).
Almost surely, 2121103232013 is an apocalyptic number.
It is an amenable number.
121103232013 is a deficient number, since it is larger than the sum of its proper divisors (1).
121103232013 is an equidigital number, since it uses as much as digits as its factorization.
121103232013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 121103232013 its reverse (310232301121), we get a palindrome (431335533134).
The spelling of 121103232013 in words is "one hundred twenty-one billion, one hundred three million, two hundred thirty-two thousand, thirteen".
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