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12110412133 is a prime number
BaseRepresentation
bin10110100011101011…
…00011100101100101
31011020222212200022201
423101311203211211
5144300231142013
65321412054501
7606051543001
oct132165434545
934228780281
1012110412133
115155014976
12241b904431
1311accb2651
1482c55d701
154ad2d03dd
hex2d1d63965

12110412133 has 2 divisors, whose sum is σ = 12110412134. Its totient is φ = 12110412132.

The previous prime is 12110412107. The next prime is 12110412173. The reversal of 12110412133 is 33121401121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6786958689 + 5323453444 = 82383^2 + 72962^2 .

It is a cyclic number.

It is not a de Polignac number, because 12110412133 - 25 = 12110412101 is a prime.

It is a super-2 number, since 2×121104121332 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12110412133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12110412103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055206066 + 6055206067.

It is an arithmetic number, because the mean of its divisors is an integer number (6055206067).

Almost surely, 212110412133 is an apocalyptic number.

It is an amenable number.

12110412133 is a deficient number, since it is larger than the sum of its proper divisors (1).

12110412133 is an equidigital number, since it uses as much as digits as its factorization.

12110412133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 12110412133 its reverse (33121401121), we get a palindrome (45231813254).

The spelling of 12110412133 in words is "twelve billion, one hundred ten million, four hundred twelve thousand, one hundred thirty-three".