12110433121 has 2 divisors, whose sum is σ = 12110433122. Its totient is φ = 12110433120.

The previous prime is 12110433113. The next prime is 12110433131. The reversal of 12110433121 is 12133401121.

12110433121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11050214400 + 1060218721 = 105120^2 + 32561^2 .

It is a cyclic number.

It is not a de Polignac number, because 12110433121 - 2³ = 12110433113 is a prime.

It is not a weakly prime, because it can be changed into another prime (12110433131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055216560 + 6055216561.

It is an arithmetic number, because the mean of its divisors is an integer number (6055216561).

Almost surely, 2^12110433121 is an apocalyptic number.

It is an amenable number.

12110433121 is a deficient number, since it is larger than the sum of its proper divisors (1).

12110433121 is an equidigital number, since it uses as much as digits as its factorization.

12110433121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 12110433121 its reverse (12133401121), we get a palindrome (24243834242).

The spelling of 12110433121 in words is "twelve billion, one hundred ten million, four hundred thirty-three thousand, one hundred twenty-one".