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121104331331 = 318138071151
BaseRepresentation
bin111000011001001100…
…0010111001001000011
3102120120222011110021212
41300302120113021003
53441010202100311
6131345022040335
711515035555164
oct1606230271103
9376528143255
10121104331331
11473a6268645
121b5797190ab
13b55cc23669
145c0bc9176b
15323bde4c8b
hex1c32617243

121104331331 has 4 divisors (see below), whose sum is σ = 121142405664. Its totient is φ = 121066257000.

The previous prime is 121104331319. The next prime is 121104331333. The reversal of 121104331331 is 133133401121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 121104331331 - 230 = 120030589507 is a prime.

It is a super-2 number, since 2×1211043313312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 121104331297 and 121104331306.

It is not an unprimeable number, because it can be changed into a prime (121104331333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19032395 + ... + 19038756.

It is an arithmetic number, because the mean of its divisors is an integer number (30285601416).

Almost surely, 2121104331331 is an apocalyptic number.

121104331331 is a deficient number, since it is larger than the sum of its proper divisors (38074333).

121104331331 is an equidigital number, since it uses as much as digits as its factorization.

121104331331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38074332.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 121104331331 its reverse (133133401121), we get a palindrome (254237732452).

The spelling of 121104331331 in words is "one hundred twenty-one billion, one hundred four million, three hundred thirty-one thousand, three hundred thirty-one".

Divisors: 1 3181 38071151 121104331331