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121104433 is a prime number
BaseRepresentation
bin1110011011111…
…10100000110001
322102212202001101
413031332200301
5222000320213
620003404401
73000241102
oct715764061
9272782041
10121104433
11623a660a
1234683701
131c122838
14121263a9
15a972bdd
hex737e831

121104433 has 2 divisors, whose sum is σ = 121104434. Its totient is φ = 121104432.

The previous prime is 121104421. The next prime is 121104449. The reversal of 121104433 is 334401121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 85248289 + 35856144 = 9233^2 + 5988^2 .

It is a cyclic number.

It is not a de Polignac number, because 121104433 - 29 = 121103921 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 121104433.

It is not a weakly prime, because it can be changed into another prime (121104463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60552216 + 60552217.

It is an arithmetic number, because the mean of its divisors is an integer number (60552217).

Almost surely, 2121104433 is an apocalyptic number.

It is an amenable number.

121104433 is a deficient number, since it is larger than the sum of its proper divisors (1).

121104433 is an equidigital number, since it uses as much as digits as its factorization.

121104433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 19.

The square root of 121104433 is about 11004.7459307337. The cubic root of 121104433 is about 494.7509994811.

Adding to 121104433 its reverse (334401121), we get a palindrome (455505554).

The spelling of 121104433 in words is "one hundred twenty-one million, one hundred four thousand, four hundred thirty-three".