Base | Representation |
---|---|
bin | 10001100111111011001… |
… | …100010100010010011111 |
3 | 11021210001122112122100021 |
4 | 101213323030110102133 |
5 | 124320313112321343 |
6 | 2324212142413011 |
7 | 153333122111410 |
oct | 21477314242237 |
9 | 4253048478307 |
10 | 1211100120223 |
11 | 427696498774 |
12 | 176876b91167 |
13 | 8a28b198796 |
14 | 4289081b807 |
15 | 217844550ed |
hex | 119fb31449f |
1211100120223 has 4 divisors (see below), whose sum is σ = 1384114423120. Its totient is φ = 1038085817328.
The previous prime is 1211100120221. The next prime is 1211100120233. The reversal of 1211100120223 is 3220210011121.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1211100120223 - 21 = 1211100120221 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1211100120197 and 1211100120206.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1211100120221) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 86507151438 + ... + 86507151451.
It is an arithmetic number, because the mean of its divisors is an integer number (346028605780).
Almost surely, 21211100120223 is an apocalyptic number.
1211100120223 is a deficient number, since it is larger than the sum of its proper divisors (173014302897).
1211100120223 is an equidigital number, since it uses as much as digits as its factorization.
1211100120223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 173014302896.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 1211100120223 its reverse (3220210011121), we get a palindrome (4431310131344).
The spelling of 1211100120223 in words is "one trillion, two hundred eleven billion, one hundred million, one hundred twenty thousand, two hundred twenty-three".
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