1211100132113 has 2 divisors, whose sum is σ = 1211100132114. Its totient is φ = 1211100132112.

The previous prime is 1211100132103. The next prime is 1211100132139. The reversal of 1211100132113 is 3112310011121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 652204838464 + 558895293649 = 807592^2 + 747593^2 .

It is a cyclic number.

It is not a de Polignac number, because 1211100132113 - 2¹⁰ = 1211100131089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1211100132091 and 1211100132100.

It is not a weakly prime, because it can be changed into another prime (1211100132103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605550066056 + 605550066057.

It is an arithmetic number, because the mean of its divisors is an integer number (605550066057).

Almost surely, 2^{1211100132113} is an apocalyptic number.

It is an amenable number.

1211100132113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211100132113 is an equidigital number, since it uses as much as digits as its factorization.

1211100132113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 1211100132113 its reverse (3112310011121), we get a palindrome (4323410143234).

The spelling of 1211100132113 in words is "one trillion, two hundred eleven billion, one hundred million, one hundred thirty-two thousand, one hundred thirteen".