Base | Representation |
---|---|
bin | 1011000000111101000010… |
… | …0000100101100111010111 |
3 | 1120212210122011212202120112 |
4 | 2300033100200211213113 |
5 | 3041411322304323111 |
6 | 41431415513153235 |
7 | 2356664100024002 |
oct | 260172040454727 |
9 | 46783564782515 |
10 | 12111011011031 |
11 | 394a283a89519 |
12 | 14372410bb81b |
13 | 69b0a94b076a |
14 | 2dc267178539 |
15 | 16007db71e8b |
hex | b03d08259d7 |
12111011011031 has 2 divisors, whose sum is σ = 12111011011032. Its totient is φ = 12111011011030.
The previous prime is 12111011011007. The next prime is 12111011011039. The reversal of 12111011011031 is 13011011011121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12111011011031 is a prime.
It is a super-2 number, since 2×121110110110312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12111011010997 and 12111011011015.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12111011011039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055505505515 + 6055505505516.
It is an arithmetic number, because the mean of its divisors is an integer number (6055505505516).
Almost surely, 212111011011031 is an apocalyptic number.
12111011011031 is a deficient number, since it is larger than the sum of its proper divisors (1).
12111011011031 is an equidigital number, since it uses as much as digits as its factorization.
12111011011031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6, while the sum is 14.
Adding to 12111011011031 its reverse (13011011011121), we get a palindrome (25122022022152).
The spelling of 12111011011031 in words is "twelve trillion, one hundred eleven billion, eleven million, eleven thousand, thirty-one".
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