12111013120303 has 4 divisors (see below), whose sum is σ = 12111020083008. Its totient is φ = 12111006157600.

The previous prime is 12111013120253. The next prime is 12111013120319. The reversal of 12111013120303 is 30302131011121.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12111013120303 is a prime.

It is a super-3 number, since 3×12111013120303³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12111013120103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1599975 + ... + 5175127.

It is an arithmetic number, because the mean of its divisors is an integer number (3027755020752).

Almost surely, 2^{12111013120303} is an apocalyptic number.

12111013120303 is a deficient number, since it is larger than the sum of its proper divisors (6962705).

12111013120303 is an equidigital number, since it uses as much as digits as its factorization.

12111013120303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6962704.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 12111013120303 its reverse (30302131011121), we get a palindrome (42413144131424).

The spelling of 12111013120303 in words is "twelve trillion, one hundred eleven billion, thirteen million, one hundred twenty thousand, three hundred three".