Base | Representation |
---|---|
bin | 1011000000111101000100… |
… | …0010111010111111000001 |
3 | 1120212210122210211000211122 |
4 | 2300033101002322333001 |
5 | 3041411332110331312 |
6 | 41431420434122025 |
7 | 2356664236361213 |
oct | 260172102727701 |
9 | 46783583730748 |
10 | 12111020011457 |
11 | 394a289076694 |
12 | 1437244120315 |
13 | 69b0ab312363 |
14 | 2dc26843c5b3 |
15 | 16007e84db72 |
hex | b03d10bafc1 |
12111020011457 has 2 divisors, whose sum is σ = 12111020011458. Its totient is φ = 12111020011456.
The previous prime is 12111020011429. The next prime is 12111020011463. The reversal of 12111020011457 is 75411002011121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10384886508481 + 1726133502976 = 3222559^2 + 1313824^2 .
It is a cyclic number.
It is not a de Polignac number, because 12111020011457 - 230 = 12109946269633 is a prime.
It is a super-2 number, since 2×121110200114572 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12111020011427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055510005728 + 6055510005729.
It is an arithmetic number, because the mean of its divisors is an integer number (6055510005729).
Almost surely, 212111020011457 is an apocalyptic number.
It is an amenable number.
12111020011457 is a deficient number, since it is larger than the sum of its proper divisors (1).
12111020011457 is an equidigital number, since it uses as much as digits as its factorization.
12111020011457 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 560, while the sum is 26.
Adding to 12111020011457 its reverse (75411002011121), we get a palindrome (87522022022578).
The spelling of 12111020011457 in words is "twelve trillion, one hundred eleven billion, twenty million, eleven thousand, four hundred fifty-seven".
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