12111062264803 has 2 divisors, whose sum is σ = 12111062264804. Its totient is φ = 12111062264802.

The previous prime is 12111062264767. The next prime is 12111062264839. The reversal of 12111062264803 is 30846226011121.

12111062264803 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (12111062264767) and next prime (12111062264839).

It is a cyclic number.

It is not a de Polignac number, because 12111062264803 - 2³³ = 12102472330211 is a prime.

It is not a weakly prime, because it can be changed into another prime (12111062264893) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055531132401 + 6055531132402.

It is an arithmetic number, because the mean of its divisors is an integer number (6055531132402).

Almost surely, 2^{12111062264803} is an apocalyptic number.

12111062264803 is a deficient number, since it is larger than the sum of its proper divisors (1).

12111062264803 is an equidigital number, since it uses as much as digits as its factorization.

12111062264803 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27648, while the sum is 37.

Adding to 12111062264803 its reverse (30846226011121), we get a palindrome (42957288275924).

The spelling of 12111062264803 in words is "twelve trillion, one hundred eleven billion, sixty-two million, two hundred sixty-four thousand, eight hundred three".