Base | Representation |
---|---|
bin | 11011100010011001100000… |
… | …110000000010111001101111 |
3 | 120212211002221120012002220202 |
4 | 123202121200300002321233 |
5 | 111333241023410121033 |
6 | 1105325402030104115 |
7 | 34336663143055346 |
oct | 3342314060027157 |
9 | 525732846162822 |
10 | 121111111020143 |
11 | 35653a2a8a1082 |
12 | 1170018a04b03b |
13 | 527696213107a |
14 | 21c9b48066b5d |
15 | e005a07c58e8 |
hex | 6e2660c02e6f |
121111111020143 has 2 divisors, whose sum is σ = 121111111020144. Its totient is φ = 121111111020142.
The previous prime is 121111111020037. The next prime is 121111111020187. The reversal of 121111111020143 is 341020111111121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121111111020143 - 212 = 121111111016047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121111111020443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60555555510071 + 60555555510072.
It is an arithmetic number, because the mean of its divisors is an integer number (60555555510072).
Almost surely, 2121111111020143 is an apocalyptic number.
121111111020143 is a deficient number, since it is larger than the sum of its proper divisors (1).
121111111020143 is an equidigital number, since it uses as much as digits as its factorization.
121111111020143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 20.
Adding to 121111111020143 its reverse (341020111111121), we get a palindrome (462131222131264).
The spelling of 121111111020143 in words is "one hundred twenty-one trillion, one hundred eleven billion, one hundred eleven million, twenty thousand, one hundred forty-three".
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