Base | Representation |
---|---|
bin | 10001100111111011111… |
… | …010011100011010010001 |
3 | 11021210002111021222022001 |
4 | 101213323322130122101 |
5 | 124320324211241423 |
6 | 2324213253514001 |
7 | 153333326642626 |
oct | 21477372343221 |
9 | 4253074258261 |
10 | 1211112212113 |
11 | 4276a22a7571 |
12 | 17687b042901 |
13 | 8a29084054b |
14 | 4289228834d |
15 | 21785542cad |
hex | 119fbe9c691 |
1211112212113 has 2 divisors, whose sum is σ = 1211112212114. Its totient is φ = 1211112212112.
The previous prime is 1211112212069. The next prime is 1211112212153. The reversal of 1211112212113 is 3112122111121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1140726530304 + 70385681809 = 1068048^2 + 265303^2 .
It is a cyclic number.
It is not a de Polignac number, because 1211112212113 - 217 = 1211112081041 is a prime.
It is not a weakly prime, because it can be changed into another prime (1211112212153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605556106056 + 605556106057.
It is an arithmetic number, because the mean of its divisors is an integer number (605556106057).
Almost surely, 21211112212113 is an apocalyptic number.
It is an amenable number.
1211112212113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211112212113 is an equidigital number, since it uses as much as digits as its factorization.
1211112212113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 48, while the sum is 19.
Adding to 1211112212113 its reverse (3112122111121), we get a palindrome (4323234323234).
The spelling of 1211112212113 in words is "one trillion, two hundred eleven billion, one hundred twelve million, two hundred twelve thousand, one hundred thirteen".
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