Base | Representation |
---|---|
bin | 1011000000111101110010… |
… | …0110111110101110010100 |
3 | 1120212211011022212100101021 |
4 | 2300033130212332232110 |
5 | 3041412231241411312 |
6 | 41431452004210524 |
7 | 2360002113354310 |
oct | 260173446765624 |
9 | 46784138770337 |
10 | 12111214013332 |
11 | 394a378632115 |
12 | 1437299099a44 |
13 | 69b10c579475 |
14 | 2dc2860dcb40 |
15 | 1600918c0c07 |
hex | b03dc9beb94 |
12111214013332 has 24 divisors (see below), whose sum is σ = 24349247032320. Its totient is φ = 5163344790240.
The previous prime is 12111214013321. The next prime is 12111214013351. The reversal of 12111214013332 is 23331041211121.
It is a junction number, because it is equal to n+sod(n) for n = 12111214013297 and 12111214013306.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1132307107 + ... + 1132317802.
It is an arithmetic number, because the mean of its divisors is an integer number (1014551959680).
Almost surely, 212111214013332 is an apocalyptic number.
It is an amenable number.
12111214013332 is an abundant number, since it is smaller than the sum of its proper divisors (12238033018988).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12111214013332 is a wasteful number, since it uses less digits than its factorization.
12111214013332 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2264625111 (or 2264625109 counting only the distinct ones).
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 12111214013332 its reverse (23331041211121), we get a palindrome (35442255224453).
The spelling of 12111214013332 in words is "twelve trillion, one hundred eleven billion, two hundred fourteen million, thirteen thousand, three hundred thirty-two".
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