Base | Representation |
---|---|
bin | 11011100010011010100001… |
… | …101110011100100011111101 |
3 | 120212211012202112101220210102 |
4 | 123202122201232130203331 |
5 | 111333300241441314442 |
6 | 1105330102130450445 |
7 | 34340032150546133 |
oct | 3342324156344375 |
9 | 525735675356712 |
10 | 121112201119997 |
11 | 3565443a16424a |
12 | 11700433133a25 |
13 | 5276aa6c26779 |
14 | 21c9c0cb49753 |
15 | e00616353232 |
hex | 6e26a1b9c8fd |
121112201119997 has 2 divisors, whose sum is σ = 121112201119998. Its totient is φ = 121112201119996.
The previous prime is 121112201119991. The next prime is 121112201120083. The reversal of 121112201119997 is 799911102211121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 82334318278276 + 38777882841721 = 9073826^2 + 6227189^2 .
It is a cyclic number.
It is not a de Polignac number, because 121112201119997 - 214 = 121112201103613 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121112201119991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60556100559998 + 60556100559999.
It is an arithmetic number, because the mean of its divisors is an integer number (60556100559999).
Almost surely, 2121112201119997 is an apocalyptic number.
It is an amenable number.
121112201119997 is a deficient number, since it is larger than the sum of its proper divisors (1).
121112201119997 is an equidigital number, since it uses as much as digits as its factorization.
121112201119997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40824, while the sum is 47.
The spelling of 121112201119997 in words is "one hundred twenty-one trillion, one hundred twelve billion, two hundred one million, one hundred nineteen thousand, nine hundred ninety-seven".
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