Base | Representation |
---|---|
bin | 10001100111111100100… |
… | …100000011011111110001 |
3 | 11021210010020211011021001 |
4 | 101213330210003133301 |
5 | 124320340004320423 |
6 | 2324214323402001 |
7 | 153333521443444 |
oct | 21477444033761 |
9 | 4253106734231 |
10 | 1211123120113 |
11 | 4276a8477945 |
12 | 176882823301 |
13 | 8a292b8c49a |
14 | 428938c765b |
15 | 21786499cad |
hex | 119fc9037f1 |
1211123120113 has 2 divisors, whose sum is σ = 1211123120114. Its totient is φ = 1211123120112.
The previous prime is 1211123120087. The next prime is 1211123120117. The reversal of 1211123120113 is 3110213211121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 736330461409 + 474792658704 = 858097^2 + 689052^2 .
It is an emirp because it is prime and its reverse (3110213211121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1211123120113 - 29 = 1211123119601 is a prime.
It is not a weakly prime, because it can be changed into another prime (1211123120117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605561560056 + 605561560057.
It is an arithmetic number, because the mean of its divisors is an integer number (605561560057).
Almost surely, 21211123120113 is an apocalyptic number.
It is an amenable number.
1211123120113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211123120113 is an equidigital number, since it uses as much as digits as its factorization.
1211123120113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 1211123120113 its reverse (3110213211121), we get a palindrome (4321336331234).
The spelling of 1211123120113 in words is "one trillion, two hundred eleven billion, one hundred twenty-three million, one hundred twenty thousand, one hundred thirteen".
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