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12111300001003 = 71730185714429
BaseRepresentation
bin1011000000111110000110…
…1110111111110011101011
31120212211101022122222021211
42300033201232333303223
53041412420300013003
641431504315213551
72360004206266240
oct260174156776353
946784338588254
1012111300001003
11394a412122a05
121437301a472b7
1369b124325048
142dc2936c35c7
1516009920896d
hexb03e1bbfceb

12111300001003 has 4 divisors (see below), whose sum is σ = 13841485715440. Its totient is φ = 10381114286568.

The previous prime is 12111300001001. The next prime is 12111300001117. The reversal of 12111300001003 is 30010000311121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12111300001003 - 21 = 12111300001001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12111300001001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 865092857208 + ... + 865092857221.

It is an arithmetic number, because the mean of its divisors is an integer number (3460371428860).

Almost surely, 212111300001003 is an apocalyptic number.

12111300001003 is a deficient number, since it is larger than the sum of its proper divisors (1730185714437).

12111300001003 is an equidigital number, since it uses as much as digits as its factorization.

12111300001003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1730185714436.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 12111300001003 its reverse (30010000311121), we get a palindrome (42121300312124).

The spelling of 12111300001003 in words is "twelve trillion, one hundred eleven billion, three hundred million, one thousand, three".

Divisors: 1 7 1730185714429 12111300001003