Base | Representation |
---|---|
bin | 1011000000111110000111… |
… | …0111001000000110100101 |
3 | 1120212211101110200020122120 |
4 | 2300033201313020012211 |
5 | 3041412421321212013 |
6 | 41431504433020153 |
7 | 2360004233353401 |
oct | 260174167100645 |
9 | 46784343606576 |
10 | 12111302132133 |
11 | 394a413349076 |
12 | 14373026b4659 |
13 | 69b1248c0079 |
14 | 2dc293aba101 |
15 | 1600994ca123 |
hex | b03e1dc81a5 |
12111302132133 has 16 divisors (see below), whose sum is σ = 16877729518080. Its totient is φ = 7710672342384.
The previous prime is 12111302132119. The next prime is 12111302132159. The reversal of 12111302132133 is 33123120311121.
It is not a de Polignac number, because 12111302132133 - 213 = 12111302123941 is a prime.
It is a super-2 number, since 2×121113021321332 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12111302132333) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 141739291 + ... + 141824712.
It is an arithmetic number, because the mean of its divisors is an integer number (1054858094880).
Almost surely, 212111302132133 is an apocalyptic number.
It is an amenable number.
12111302132133 is a deficient number, since it is larger than the sum of its proper divisors (4766427385947).
12111302132133 is a wasteful number, since it uses less digits than its factorization.
12111302132133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 283564648.
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 12111302132133 its reverse (33123120311121), we get a palindrome (45234422443254).
The spelling of 12111302132133 in words is "twelve trillion, one hundred eleven billion, three hundred two million, one hundred thirty-two thousand, one hundred thirty-three".
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