Base | Representation |
---|---|
bin | 1011000000111110000111… |
… | …0111100000110000001111 |
3 | 1120212211101110212101011012 |
4 | 2300033201313200300033 |
5 | 3041412421332424403 |
6 | 41431504435115435 |
7 | 2360004234253643 |
oct | 260174167406017 |
9 | 46784343771135 |
10 | 12111302233103 |
11 | 394a413407a17 |
12 | 1437302742b7b |
13 | 69b124927008 |
14 | 2dc293b04c23 |
15 | 1600994e9ed8 |
hex | b03e1de0c0f |
12111302233103 has 32 divisors (see below), whose sum is σ = 13515353625600. Its totient is φ = 10800408326400.
The previous prime is 12111302233073. The next prime is 12111302233117. The reversal of 12111302233103 is 30133220311121.
It is a cyclic number.
It is not a de Polignac number, because 12111302233103 - 218 = 12111301970959 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (23).
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12111302233133) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 16424843 + ... + 17146371.
It is an arithmetic number, because the mean of its divisors is an integer number (422354800800).
Almost surely, 212111302233103 is an apocalyptic number.
12111302233103 is a deficient number, since it is larger than the sum of its proper divisors (1404051392497).
12111302233103 is a wasteful number, since it uses less digits than its factorization.
12111302233103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 722183.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 12111302233103 its reverse (30133220311121), we get a palindrome (42244522544224).
The spelling of 12111302233103 in words is "twelve trillion, one hundred eleven billion, three hundred two million, two hundred thirty-three thousand, one hundred three".
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