12111322120103 has 4 divisors (see below), whose sum is σ = 12154422910848. Its totient is φ = 12068221329360.

The previous prime is 12111322120091. The next prime is 12111322120127. The reversal of 12111322120103 is 30102122311121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12111322120103 - 2¹⁴ = 12111322103719 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12111322120193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21550394951 + ... + 21550395512.

It is an arithmetic number, because the mean of its divisors is an integer number (3038605727712).

Almost surely, 2^{12111322120103} is an apocalyptic number.

12111322120103 is a deficient number, since it is larger than the sum of its proper divisors (43100790745).

12111322120103 is an equidigital number, since it uses as much as digits as its factorization.

12111322120103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43100790744.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 12111322120103 its reverse (30102122311121), we get a palindrome (42213444431224).

The spelling of 12111322120103 in words is "twelve trillion, one hundred eleven billion, three hundred twenty-two million, one hundred twenty thousand, one hundred three".