Base | Representation |
---|---|
bin | 111000011001011101… |
… | …1000111011101010011 |
3 | 102120121121022022221220 |
4 | 1300302323013131103 |
5 | 3441020020122011 |
6 | 131345545220123 |
7 | 11515206162243 |
oct | 1606273073523 |
9 | 376547268856 |
10 | 121113442131 |
11 | 47400420730 |
12 | 1b580791643 |
13 | b561a93576 |
14 | 5c0d183b23 |
15 | 323cae4506 |
hex | 1c32ec7753 |
121113442131 has 8 divisors (see below), whose sum is σ = 176165006784. Its totient is φ = 73402086120.
The previous prime is 121113442127. The next prime is 121113442133. The reversal of 121113442131 is 131244311121.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 121113442131 - 22 = 121113442127 is a prime.
It is a super-2 number, since 2×1211134421312 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (121113442133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1835052121 + ... + 1835052186.
It is an arithmetic number, because the mean of its divisors is an integer number (22020625848).
Almost surely, 2121113442131 is an apocalyptic number.
121113442131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
121113442131 is a deficient number, since it is larger than the sum of its proper divisors (55051564653).
121113442131 is a wasteful number, since it uses less digits than its factorization.
121113442131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3670104321.
The product of its digits is 576, while the sum is 24.
Adding to 121113442131 its reverse (131244311121), we get a palindrome (252357753252).
The spelling of 121113442131 in words is "one hundred twenty-one billion, one hundred thirteen million, four hundred forty-two thousand, one hundred thirty-one".
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