12111410653 has 4 divisors (see below), whose sum is σ = 12111903648. Its totient is φ = 12110917660.

The previous prime is 12111410629. The next prime is 12111410671. The reversal of 12111410653 is 35601411121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35601411121 = 1879 ⋅18946999.

It is a cyclic number.

It is not a de Polignac number, because 12111410653 - 2¹³ = 12111402461 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12111410693) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 207601 + ... + 259462.

It is an arithmetic number, because the mean of its divisors is an integer number (3027975912).

Almost surely, 2^12111410653 is an apocalyptic number.

It is an amenable number.

12111410653 is a deficient number, since it is larger than the sum of its proper divisors (492995).

12111410653 is an equidigital number, since it uses as much as digits as its factorization.

12111410653 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 492994.

The product of its (nonzero) digits is 720, while the sum is 25.

Adding to 12111410653 its reverse (35601411121), we get a palindrome (47712821774).

The spelling of 12111410653 in words is "twelve billion, one hundred eleven million, four hundred ten thousand, six hundred fifty-three".