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12111716565717 = 34037238855239
BaseRepresentation
bin1011000000111111101010…
…0100000100001011010101
31120212212110100111122122120
42300033322210010023111
53041414243420100332
641432013515450153
72360020425111516
oct260177244041325
946785410448576
1012111716565717
11394a60628216a
1214373b9456959
1369b18c716242
142dc2d2b5aa0d
151600c0a9032c
hexb03fa9042d5

12111716565717 has 4 divisors (see below), whose sum is σ = 16148955420960. Its totient is φ = 8074477710476.

The previous prime is 12111716565713. The next prime is 12111716565731. The reversal of 12111716565717 is 71756561711121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12111716565717 - 22 = 12111716565713 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12111716565717.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12111716565713) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2018619427617 + ... + 2018619427622.

It is an arithmetic number, because the mean of its divisors is an integer number (4037238855240).

Almost surely, 212111716565717 is an apocalyptic number.

It is an amenable number.

12111716565717 is a deficient number, since it is larger than the sum of its proper divisors (4037238855243).

12111716565717 is an equidigital number, since it uses as much as digits as its factorization.

12111716565717 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4037238855242.

The product of its digits is 617400, while the sum is 51.

The spelling of 12111716565717 in words is "twelve trillion, one hundred eleven billion, seven hundred sixteen million, five hundred sixty-five thousand, seven hundred seventeen".

Divisors: 1 3 4037238855239 12111716565717