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12111971953 is a prime number
BaseRepresentation
bin10110100011110111…
…00000011001110001
31011021002210220222211
423101323200121301
5144301131100303
65321505332121
7606101030404
oct132173403161
934232726884
1012111971953
11515598a884
122420337041
1311b040a613
1482c847d3b
154ad4dc66d
hex2d1ee0671

12111971953 has 2 divisors, whose sum is σ = 12111971954. Its totient is φ = 12111971952.

The previous prime is 12111971947. The next prime is 12111972013. The reversal of 12111971953 is 35917911121.

12111971953 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8703397264 + 3408574689 = 93292^2 + 58383^2 .

It is an emirp because it is prime and its reverse (35917911121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12111971953 - 225 = 12078417521 is a prime.

It is not a weakly prime, because it can be changed into another prime (12111971353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055985976 + 6055985977.

It is an arithmetic number, because the mean of its divisors is an integer number (6055985977).

Almost surely, 212111971953 is an apocalyptic number.

It is an amenable number.

12111971953 is a deficient number, since it is larger than the sum of its proper divisors (1).

12111971953 is an equidigital number, since it uses as much as digits as its factorization.

12111971953 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 17010, while the sum is 40.

It can be divided in two parts, 12111 and 971953, that added together give a square (984064 = 9922).

The spelling of 12111971953 in words is "twelve billion, one hundred eleven million, nine hundred seventy-one thousand, nine hundred fifty-three".