12112004013131 has 8 divisors (see below), whose sum is σ = 13286911464000. Its totient is φ = 10949399258440.

The previous prime is 12112004013127. The next prime is 12112004013133. The reversal of 12112004013131 is 13131040021121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12112004013131 - 2² = 12112004013127 is a prime.

It is a super-2 number, since 2×12112004013131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12112004013133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3075671981 + ... + 3075675918.

It is an arithmetic number, because the mean of its divisors is an integer number (1660863933000).

Almost surely, 2^{12112004013131} is an apocalyptic number.

12112004013131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

12112004013131 is a deficient number, since it is larger than the sum of its proper divisors (1174907450869).

12112004013131 is a wasteful number, since it uses less digits than its factorization.

12112004013131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6151348089.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 12112004013131 its reverse (13131040021121), we get a palindrome (25243044034252).

The spelling of 12112004013131 in words is "twelve trillion, one hundred twelve billion, four million, thirteen thousand, one hundred thirty-one".