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12112010010017 is a prime number
BaseRepresentation
bin1011000001000000110000…
…0011011101110110100001
31120212220012210200011112222
42300100030003131312201
53041420344030310032
641432103001200425
72360030620255331
oct260201403356641
946786183604488
1012112010010017
11394a746989215
12143747b790115
1369b20845a118
142dc31db050c1
151600db706a12
hexb040c0ddda1

12112010010017 has 2 divisors, whose sum is σ = 12112010010018. Its totient is φ = 12112010010016.

The previous prime is 12112010010011. The next prime is 12112010010047. The reversal of 12112010010017 is 71001001021121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6555448450321 + 5556561559696 = 2560361^2 + 2357236^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12112010010017 is a prime.

It is a super-3 number, since 3×121120100100173 (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12112010009977 and 12112010010004.

It is not a weakly prime, because it can be changed into another prime (12112010010011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056005005008 + 6056005005009.

It is an arithmetic number, because the mean of its divisors is an integer number (6056005005009).

Almost surely, 212112010010017 is an apocalyptic number.

It is an amenable number.

12112010010017 is a deficient number, since it is larger than the sum of its proper divisors (1).

12112010010017 is an equidigital number, since it uses as much as digits as its factorization.

12112010010017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28, while the sum is 17.

Adding to 12112010010017 its reverse (71001001021121), we get a palindrome (83113011031138).

The spelling of 12112010010017 in words is "twelve trillion, one hundred twelve billion, ten million, ten thousand, seventeen".