Base | Representation |
---|---|
bin | 1110011100000… |
… | …10010110010011 |
3 | 22102220112121101 |
4 | 13032002112103 |
5 | 222001321042 |
6 | 20004005231 |
7 | 3000334651 |
oct | 716022623 |
9 | 272815541 |
10 | 121120147 |
11 | 624073a5 |
12 | 34690817 |
13 | 1c129a35 |
14 | 1212bdd1 |
15 | a9776b7 |
hex | 7382593 |
121120147 has 2 divisors, whose sum is σ = 121120148. Its totient is φ = 121120146.
The previous prime is 121120141. The next prime is 121120169. The reversal of 121120147 is 741021121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 121120147 - 211 = 121118099 is a prime.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (121120141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60560073 + 60560074.
It is an arithmetic number, because the mean of its divisors is an integer number (60560074).
Almost surely, 2121120147 is an apocalyptic number.
121120147 is a deficient number, since it is larger than the sum of its proper divisors (1).
121120147 is an equidigital number, since it uses as much as digits as its factorization.
121120147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 19.
The square root of 121120147 is about 11005.4598722634. The cubic root of 121120147 is about 494.7723974893.
Adding to 121120147 its reverse (741021121), we get a palindrome (862141268).
The spelling of 121120147 in words is "one hundred twenty-one million, one hundred twenty thousand, one hundred forty-seven".
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