12112100014003 has 8 divisors (see below), whose sum is σ = 13429809852336. Its totient is φ = 10830491815200.

The previous prime is 12112100013997. The next prime is 12112100014037. The reversal of 12112100014003 is 30041000121121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12112100014003 - 2⁵ = 12112100013971 is a prime.

It is a super-2 number, since 2×12112100014003² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12112100084003) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9025409176 + ... + 9025410517.

It is an arithmetic number, because the mean of its divisors is an integer number (1678726231542).

Almost surely, 2^{12112100014003} is an apocalyptic number.

12112100014003 is a deficient number, since it is larger than the sum of its proper divisors (1317709838333).

12112100014003 is a wasteful number, since it uses less digits than its factorization.

12112100014003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18050819765.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 12112100014003 its reverse (30041000121121), we get a palindrome (42153100135124).

The spelling of 12112100014003 in words is "twelve trillion, one hundred twelve billion, one hundred million, fourteen thousand, three".