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121121021009993 is a prime number
BaseRepresentation
bin11011100010100010101111…
…011011101010000001001001
3120212212001112012120202022212
4123202202233123222001021
5111333421322334304433
61105334121235354505
734340463545433134
oct3342425733520111
9525761465522285
10121121021009993
1135658155818134
1211702094a52a35
135277881294aa4
1421ca40827921b
15e00980803d48
hex6e28af6ea049

121121021009993 has 2 divisors, whose sum is σ = 121121021009994. Its totient is φ = 121121021009992.

The previous prime is 121121021009977. The next prime is 121121021010001. The reversal of 121121021009993 is 399900120121121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111232184808889 + 9888836201104 = 10546667^2 + 3144652^2 .

It is a cyclic number.

It is not a de Polignac number, because 121121021009993 - 24 = 121121021009977 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 121121021009993.

It is not a weakly prime, because it can be changed into another prime (121121021509993) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60560510504996 + 60560510504997.

It is an arithmetic number, because the mean of its divisors is an integer number (60560510504997).

Almost surely, 2121121021009993 is an apocalyptic number.

It is an amenable number.

121121021009993 is a deficient number, since it is larger than the sum of its proper divisors (1).

121121021009993 is an equidigital number, since it uses as much as digits as its factorization.

121121021009993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17496, while the sum is 41.

The spelling of 121121021009993 in words is "one hundred twenty-one trillion, one hundred twenty-one billion, twenty-one million, nine thousand, nine hundred ninety-three".