Base | Representation |
---|---|
bin | 11011100010100010110101… |
… | …111011011111110100100101 |
3 | 120212212001210210201001010110 |
4 | 123202202311323133310211 |
5 | 111333422033241121013 |
6 | 1105334140132043233 |
7 | 34340466341133015 |
oct | 3342426573376445 |
9 | 525761723631113 |
10 | 121121130020133 |
11 | 35658201303061 |
12 | 11702105463519 |
13 | 527789aa41729 |
14 | 21ca418933c45 |
15 | e0098a1882c3 |
hex | 6e28b5edfd25 |
121121130020133 has 8 divisors (see below), whose sum is σ = 161495125773696. Its totient is φ = 80747277140000.
The previous prime is 121121130020117. The next prime is 121121130020153. The reversal of 121121130020133 is 331020031121121.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 121121130020133 - 24 = 121121130020117 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (121121130020153) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 33724368 + ... + 37142633.
It is an arithmetic number, because the mean of its divisors is an integer number (20186890721712).
Almost surely, 2121121130020133 is an apocalyptic number.
It is an amenable number.
121121130020133 is a deficient number, since it is larger than the sum of its proper divisors (40373995753563).
121121130020133 is an equidigital number, since it uses as much as digits as its factorization.
121121130020133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71436715.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 121121130020133 its reverse (331020031121121), we get a palindrome (452141161141254).
The spelling of 121121130020133 in words is "one hundred twenty-one trillion, one hundred twenty-one billion, one hundred thirty million, twenty thousand, one hundred thirty-three".
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