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121121201112019 is a prime number
BaseRepresentation
bin11011100010100010111010…
…001010101100001111010011
3120212212001222202110212212021
4123202202322022230033103
5111333422204441041034
61105334151151512311
734340501163325003
oct3342427212541723
9525761882425767
10121121201112019
113565823844a489
1211702125228697
1352778ac6a3234
1421ca42415c003
15e0099152c6b4
hex6e28ba2ac3d3

121121201112019 has 2 divisors, whose sum is σ = 121121201112020. Its totient is φ = 121121201112018.

The previous prime is 121121201112011. The next prime is 121121201112031. The reversal of 121121201112019 is 910211102121121.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 121121201112019 - 23 = 121121201112011 is a prime.

It is a super-2 number, since 2×1211212011120192 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 121121201111984 and 121121201112002.

It is not a weakly prime, because it can be changed into another prime (121121201112011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60560600556009 + 60560600556010.

It is an arithmetic number, because the mean of its divisors is an integer number (60560600556010).

Almost surely, 2121121201112019 is an apocalyptic number.

121121201112019 is a deficient number, since it is larger than the sum of its proper divisors (1).

121121201112019 is an equidigital number, since it uses as much as digits as its factorization.

121121201112019 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 25.

The spelling of 121121201112019 in words is "one hundred twenty-one trillion, one hundred twenty-one billion, two hundred one million, one hundred twelve thousand, nineteen".