Base | Representation |
---|---|
bin | 11011100010100010111010… |
… | …001010101100001111011111 |
3 | 120212212001222202110212212201 |
4 | 123202202322022230033133 |
5 | 111333422204441041111 |
6 | 1105334151151512331 |
7 | 34340501163325021 |
oct | 3342427212541737 |
9 | 525761882425781 |
10 | 121121201112031 |
11 | 3565823844a49a |
12 | 117021252286a7 |
13 | 52778ac6a3243 |
14 | 21ca42415c011 |
15 | e0099152c6c1 |
hex | 6e28ba2ac3df |
121121201112031 has 2 divisors, whose sum is σ = 121121201112032. Its totient is φ = 121121201112030.
The previous prime is 121121201112019. The next prime is 121121201112071. The reversal of 121121201112031 is 130211102121121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 121121201112031 - 27 = 121121201111903 is a prime.
It is a super-2 number, since 2×1211212011120312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121121201112001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60560600556015 + 60560600556016.
It is an arithmetic number, because the mean of its divisors is an integer number (60560600556016).
Almost surely, 2121121201112031 is an apocalyptic number.
121121201112031 is a deficient number, since it is larger than the sum of its proper divisors (1).
121121201112031 is an equidigital number, since it uses as much as digits as its factorization.
121121201112031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 19.
Adding to 121121201112031 its reverse (130211102121121), we get a palindrome (251332303233152).
The spelling of 121121201112031 in words is "one hundred twenty-one trillion, one hundred twenty-one billion, two hundred one million, one hundred twelve thousand, thirty-one".
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