12112120123 has 4 divisors (see below), whose sum is σ = 12112400320. Its totient is φ = 12111839928.

The previous prime is 12112120121. The next prime is 12112120127. The reversal of 12112120123 is 32102121121.

12112120123 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12112120123 - 2¹ = 12112120121 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12112120097 and 12112120106.

It is not an unprimeable number, because it can be changed into a prime (12112120121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59988 + ... + 166801.

It is an arithmetic number, because the mean of its divisors is an integer number (3028100080).

Almost surely, 2^12112120123 is an apocalyptic number.

12112120123 is a deficient number, since it is larger than the sum of its proper divisors (280197).

12112120123 is an equidigital number, since it uses as much as digits as its factorization.

12112120123 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 280196.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 12112120123 its reverse (32102121121), we get a palindrome (44214241244).

The spelling of 12112120123 in words is "twelve billion, one hundred twelve million, one hundred twenty thousand, one hundred twenty-three".