Base | Representation |
---|---|
bin | 11011100010100010111010… |
… | …110000011101010010011011 |
3 | 120212212002000110002212102112 |
4 | 123202202322300131102123 |
5 | 111333422220004343001 |
6 | 1105334152144022535 |
7 | 34340501343430442 |
oct | 3342427260352233 |
9 | 525762013085375 |
10 | 121121211012251 |
11 | 35658242aa169a |
12 | 11702128601a4b |
13 | 52778b175b568 |
14 | 21ca4255b7d59 |
15 | e00992335cbb |
hex | 6e28bac1d49b |
121121211012251 has 2 divisors, whose sum is σ = 121121211012252. Its totient is φ = 121121211012250.
The previous prime is 121121211012181. The next prime is 121121211012301. The reversal of 121121211012251 is 152210112121121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121121211012251 - 230 = 121120137270427 is a prime.
It is not a weakly prime, because it can be changed into another prime (121121211017251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60560605506125 + 60560605506126.
It is an arithmetic number, because the mean of its divisors is an integer number (60560605506126).
Almost surely, 2121121211012251 is an apocalyptic number.
121121211012251 is a deficient number, since it is larger than the sum of its proper divisors (1).
121121211012251 is an equidigital number, since it uses as much as digits as its factorization.
121121211012251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 160, while the sum is 23.
Adding to 121121211012251 its reverse (152210112121121), we get a palindrome (273331323133372).
The spelling of 121121211012251 in words is "one hundred twenty-one trillion, one hundred twenty-one billion, two hundred eleven million, twelve thousand, two hundred fifty-one".
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