121122110122113 has 4 divisors (see below), whose sum is σ = 161496146829488. Its totient is φ = 80748073414740.

The previous prime is 121122110122073. The next prime is 121122110122127. The reversal of 121122110122113 is 311221011221121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 121122110122113 - 2¹² = 121122110118017 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 121122110122113.

It is not an unprimeable number, because it can be changed into a prime (121122110122163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20187018353683 + ... + 20187018353688.

It is an arithmetic number, because the mean of its divisors is an integer number (40374036707372).

Almost surely, 2^{121122110122113} is an apocalyptic number.

It is an amenable number.

121122110122113 is a deficient number, since it is larger than the sum of its proper divisors (40374036707375).

121122110122113 is an equidigital number, since it uses as much as digits as its factorization.

121122110122113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40374036707374.

The product of its (nonzero) digits is 96, while the sum is 21.

Adding to 121122110122113 its reverse (311221011221121), we get a palindrome (432343121343234).

The spelling of 121122110122113 in words is "one hundred twenty-one trillion, one hundred twenty-two billion, one hundred ten million, one hundred twenty-two thousand, one hundred thirteen".