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121122110122127 is a prime number
BaseRepresentation
bin11011100010100011110000…
…010110010010100010001111
3120212212011100002221101022022
4123202203300112102202033
5111333431040142402002
61105334421303040355
734340532541641152
oct3342436026224217
9525764302841268
10121122110122127
1135658664576204
12117023397400bb
1352779c5b02a3a
1421ca4acb81c99
15e009e6238ba2
hex6e28f059288f

121122110122127 has 2 divisors, whose sum is σ = 121122110122128. Its totient is φ = 121122110122126.

The previous prime is 121122110122073. The next prime is 121122110122157. The reversal of 121122110122127 is 721221011221121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 121122110122127 - 226 = 121122043013263 is a prime.

It is a super-3 number, since 3×1211221101221273 (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 121122110122096 and 121122110122105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121122110122157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60561055061063 + 60561055061064.

It is an arithmetic number, because the mean of its divisors is an integer number (60561055061064).

Almost surely, 2121122110122127 is an apocalyptic number.

121122110122127 is a deficient number, since it is larger than the sum of its proper divisors (1).

121122110122127 is an equidigital number, since it uses as much as digits as its factorization.

121122110122127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 448, while the sum is 26.

Adding to 121122110122127 its reverse (721221011221121), we get a palindrome (842343121343248).

The spelling of 121122110122127 in words is "one hundred twenty-one trillion, one hundred twenty-two billion, one hundred ten million, one hundred twenty-two thousand, one hundred twenty-seven".