Base | Representation |
---|---|
bin | 1011000001000001100000… |
… | …1110000010111100101111 |
3 | 1120212220202000201112002120 |
4 | 2300100120032002330233 |
5 | 3041421303303004444 |
6 | 41432135131524023 |
7 | 2360035646140113 |
oct | 260203016027457 |
9 | 46786660645076 |
10 | 12112214109999 |
11 | 394a841111593 |
12 | 1437517bb9613 |
13 | 69b23b81b643 |
14 | 2dc33cc73743 |
15 | 1600ee5c0b19 |
hex | b0418382f2f |
12112214109999 has 8 divisors (see below), whose sum is σ = 16168463179440. Its totient is φ = 8065387223616.
The previous prime is 12112214109991. The next prime is 12112214110049. The reversal of 12112214109999 is 99990141221121.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 12112214109999 - 23 = 12112214109991 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12112214109991) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2355542764 + ... + 2355547905.
It is an arithmetic number, because the mean of its divisors is an integer number (2021057897430).
Almost surely, 212112214109999 is an apocalyptic number.
12112214109999 is a deficient number, since it is larger than the sum of its proper divisors (4056249069441).
12112214109999 is an equidigital number, since it uses as much as digits as its factorization.
12112214109999 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4711091529.
The product of its (nonzero) digits is 209952, while the sum is 51.
The spelling of 12112214109999 in words is "twelve trillion, one hundred twelve billion, two hundred fourteen million, one hundred nine thousand, nine hundred ninety-nine".
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