Base | Representation |
---|---|
bin | 10001101000000010100… |
… | …001111100011001011111 |
3 | 11021210101020012021021101 |
4 | 101220002201330121133 |
5 | 124321041121330142 |
6 | 2324232301213531 |
7 | 153336145404235 |
oct | 21500241743137 |
9 | 4253336167241 |
10 | 1211223230047 |
11 | 427749a33a26 |
12 | 1768b02612a7 |
13 | 8a2aa84102c |
14 | 428a2d06955 |
15 | 217901720b7 |
hex | 11a0287c65f |
1211223230047 has 2 divisors, whose sum is σ = 1211223230048. Its totient is φ = 1211223230046.
The previous prime is 1211223230029. The next prime is 1211223230089. The reversal of 1211223230047 is 7400323221121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1211223230047 - 27 = 1211223229919 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1211223229997 and 1211223230024.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1211223230027) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605611615023 + 605611615024.
It is an arithmetic number, because the mean of its divisors is an integer number (605611615024).
Almost surely, 21211223230047 is an apocalyptic number.
1211223230047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211223230047 is an equidigital number, since it uses as much as digits as its factorization.
1211223230047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4032, while the sum is 28.
Adding to 1211223230047 its reverse (7400323221121), we get a palindrome (8611546451168).
The spelling of 1211223230047 in words is "one trillion, two hundred eleven billion, two hundred twenty-three million, two hundred thirty thousand, forty-seven".
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