Base | Representation |
---|---|
bin | 1011000001000001110101… |
… | …0110111000101000101011 |
3 | 1120212220222000221002120011 |
4 | 2300100131112320220223 |
5 | 3041421442340010011 |
6 | 41432151451312351 |
7 | 2360041043640154 |
oct | 260203526705053 |
9 | 46786860832504 |
10 | 12112300313131 |
11 | 394a88583a247 |
12 | 1437540a4b6b7 |
13 | 69b253641305 |
14 | 2dc34a4b292b |
15 | 160106e4c621 |
hex | b041d5b8a2b |
12112300313131 has 4 divisors (see below), whose sum is σ = 12529965841200. Its totient is φ = 11694634785064.
The previous prime is 12112300313123. The next prime is 12112300313161. The reversal of 12112300313131 is 13131300321121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12112300313131 - 23 = 12112300313123 is a prime.
It is a super-2 number, since 2×121123003131312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12112300313101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 208832763991 + ... + 208832764048.
It is an arithmetic number, because the mean of its divisors is an integer number (3132491460300).
Almost surely, 212112300313131 is an apocalyptic number.
12112300313131 is a deficient number, since it is larger than the sum of its proper divisors (417665528069).
12112300313131 is an equidigital number, since it uses as much as digits as its factorization.
12112300313131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 417665528068.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 12112300313131 its reverse (13131300321121), we get a palindrome (25243600634252).
The spelling of 12112300313131 in words is "twelve trillion, one hundred twelve billion, three hundred million, three hundred thirteen thousand, one hundred thirty-one".
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